7z+25=3z+32

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Solution for 7z+25=3z+32 equation: 



7z+25=3z+32

We move all terms to the left:

7z+25-(3z+32)=0

We get rid of parentheses

7z-3z-32+25=0

We add all the numbers together, and all the variables

4z-7=0

We move all terms containing z to the left, all other terms to the right

4z=7

z=7/4

z=1+3/4

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