7z+28-10=3z+20=4z-2

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Solution for 7z+28-10=3z+20=4z-2 equation: 



7z+28-10=3z+20=4z-2

We move all terms to the left:

7z+28-10-(3z+20)=0

We add all the numbers together, and all the variables

7z-(3z+20)+18=0

We get rid of parentheses

7z-3z-20+18=0

We add all the numbers together, and all the variables

4z-2=0

We move all terms containing z to the left, all other terms to the right

4z=2

z=2/4

z=1/2

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