7z+42=100-4z-3

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Solution for 7z+42=100-4z-3 equation: 



7z+42=100-4z-3

We move all terms to the left:

7z+42-(100-4z-3)=0

We add all the numbers together, and all the variables

7z-(-4z+97)+42=0

We get rid of parentheses

7z+4z-97+42=0

We add all the numbers together, and all the variables

11z-55=0

We move all terms containing z to the left, all other terms to the right

11z=55

z=55/11

z=5

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