7z-(2+z)=3(3z-1)

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Solution for 7z-(2+z)=3(3z-1) equation:


Simplifying
7z + -1(2 + z) = 3(3z + -1)
7z + (2 * -1 + z * -1) = 3(3z + -1)
7z + (-2 + -1z) = 3(3z + -1)

Reorder the terms:
-2 + 7z + -1z = 3(3z + -1)

Combine like terms: 7z + -1z = 6z
-2 + 6z = 3(3z + -1)

Reorder the terms:
-2 + 6z = 3(-1 + 3z)
-2 + 6z = (-1 * 3 + 3z * 3)
-2 + 6z = (-3 + 9z)

Solving
-2 + 6z = -3 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
-2 + 6z + -9z = -3 + 9z + -9z

Combine like terms: 6z + -9z = -3z
-2 + -3z = -3 + 9z + -9z

Combine like terms: 9z + -9z = 0
-2 + -3z = -3 + 0
-2 + -3z = -3

Add '2' to each side of the equation.
-2 + 2 + -3z = -3 + 2

Combine like terms: -2 + 2 = 0
0 + -3z = -3 + 2
-3z = -3 + 2

Combine like terms: -3 + 2 = -1
-3z = -1

Divide each side by '-3'.
z = 0.3333333333

Simplifying
z = 0.3333333333

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