7z-29z=9(z+16)-36(4-9z)

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Solution for 7z-29z=9(z+16)-36(4-9z) equation: 



7z-29z=9(z+16)-36(4-9z)

We move all terms to the left:

7z-29z-(9(z+16)-36(4-9z))=0

We add all the numbers together, and all the variables

7z-29z-(9(z+16)-36(-9z+4))=0

We add all the numbers together, and all the variables

-22z-(9(z+16)-36(-9z+4))=0



We calculate terms in parentheses: -(9(z+16)-36(-9z+4)), so:

9(z+16)-36(-9z+4)

We multiply parentheses

9z+324z+144-144

We add all the numbers together, and all the variables

333z

Back to the equation:

-(333z)



We add all the numbers together, and all the variables

-355z=0

z=0/-355

z=0

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