7z-3(4-z)=5(2z)+12

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Solution for 7z-3(4-z)=5(2z)+12 equation: 


Simplifying
7z + -3(4 + -1z) = 5(2z) + 12
7z + (4 * -3 + -1z * -3) = 5(2z) + 12
7z + (-12 + 3z) = 5(2z) + 12

Reorder the terms:
-12 + 7z + 3z = 5(2z) + 12

Combine like terms: 7z + 3z = 10z
-12 + 10z = 5(2z) + 12

Remove parenthesis around (2z)
-12 + 10z = 5 * 2z + 12

Multiply 5 * 2
-12 + 10z = 10z + 12

Reorder the terms:
-12 + 10z = 12 + 10z

Add '-10z' to each side of the equation.
-12 + 10z + -10z = 12 + 10z + -10z

Combine like terms: 10z + -10z = 0
-12 + 0 = 12 + 10z + -10z
-12 = 12 + 10z + -10z

Combine like terms: 10z + -10z = 0
-12 = 12 + 0
-12 = 12

Solving
-12 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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