7z-4*(z-8)=0

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Solution for 7z-4*(z-8)=0 equation: 



7z-4(z-8)=0

We multiply parentheses

7z-4z+32=0

We add all the numbers together, and all the variables

3z+32=0

We move all terms containing z to the left, all other terms to the right

3z=-32

z=-32/3

z=-10+2/3

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