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8((2x+5/5+x)-3=61
We move all terms to the left:
8((2x+5/5+x)-3-(61)=0
Domain of the equation: 5+x)-3-61!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)-3-61!=-5
x!=-5/1
x!=-5
x∈R
8((3x+1)-3-61=0
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