8((y+1)/4)+3y=0

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Solution for 8((y+1)/4)+3y=0 equation: 



8((y+1)/4)+3y=0

We add all the numbers together, and all the variables

3y+8((y+1)/4)=0

We multiply all the terms by the denominator


3y*4)+8((y+1)=0

Wy multiply elements

12y^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$

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