8(+4)-3(x+1)=7(2-x)

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Solution for 8(+4)-3(x+1)=7(2-x) equation: 



8(+4)-3(x+1)=7(2-x)

We move all terms to the left:

8(+4)-3(x+1)-(7(2-x))=0

We add all the numbers together, and all the variables

-3(x+1)-(7(-1x+2))+84=0

We multiply parentheses

-3x-(7(-1x+2))-3+84=0



We calculate terms in parentheses: -(7(-1x+2)), so:

7(-1x+2)

We multiply parentheses

-7x+14

Back to the equation:

-(-7x+14)



We add all the numbers together, and all the variables

-3x-(-7x+14)+81=0

We get rid of parentheses

-3x+7x-14+81=0

We add all the numbers together, and all the variables

4x+67=0

We move all terms containing x to the left, all other terms to the right

4x=-67

x=-67/4

x=-16+3/4

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