8(+4)-3(x+1)=7(2-x)

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Solution for 8(+4)-3(x+1)=7(2-x) equation:



8(+4)-3(x+1)=7(2-x)
We move all terms to the left:
8(+4)-3(x+1)-(7(2-x))=0
We add all the numbers together, and all the variables
-3(x+1)-(7(-1x+2))+84=0
We multiply parentheses
-3x-(7(-1x+2))-3+84=0
We calculate terms in parentheses: -(7(-1x+2)), so:
7(-1x+2)
We multiply parentheses
-7x+14
Back to the equation:
-(-7x+14)
We add all the numbers together, and all the variables
-3x-(-7x+14)+81=0
We get rid of parentheses
-3x+7x-14+81=0
We add all the numbers together, and all the variables
4x+67=0
We move all terms containing x to the left, all other terms to the right
4x=-67
x=-67/4
x=-16+3/4

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