8(-+m)+3=2(m-51/2)

Solution for 8(-+m)+3=2(m-51/2) equation:

8(-+m)+3=2(m-51/2)

We move all terms to the left:

8(-+m)+3-(2(m-51/2))=0

We add all the numbers together, and all the variables

8(+m)-(2(+m-51/2))+3=0

We multiply parentheses

8m-(2(+m-51/2))+3=0

We multiply all the terms by the denominator


8m*2))-(2(+m-51+3*2))=0

We add all the numbers together, and all the variables

8m*2))-(2(m-45))=0

We add all the numbers together, and all the variables

8m*2))-(2(m=0

Wy multiply elements

16m^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{32}=0$