8(-1+2v)-3=5-3(-v+1)

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Solution for 8(-1+2v)-3=5-3(-v+1) equation: 



8(-1+2v)-3=5-3(-v+1)

We move all terms to the left:

8(-1+2v)-3-(5-3(-v+1))=0

We add all the numbers together, and all the variables

8(2v-1)-(5-3(-1v+1))-3=0

We multiply parentheses

16v-(5-3(-1v+1))-8-3=0



We calculate terms in parentheses: -(5-3(-1v+1)), so:

5-3(-1v+1)

determiningTheFunctionDomain
-3(-1v+1)+5

We multiply parentheses

3v-3+5

We add all the numbers together, and all the variables

3v+2

Back to the equation:

-(3v+2)



We add all the numbers together, and all the variables

16v-(3v+2)-11=0

We get rid of parentheses

16v-3v-2-11=0

We add all the numbers together, and all the variables

13v-13=0

We move all terms containing v to the left, all other terms to the right

13v=13

v=13/13

v=1

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