8(-1+m)+3=2(m-22/4)

Solution for 8(-1+m)+3=2(m-22/4) equation:

8(-1+m)+3=2(m-22/4)

We move all terms to the left:

8(-1+m)+3-(2(m-22/4))=0

We add all the numbers together, and all the variables

8(m-1)-(2(+m-22/4))+3=0

We multiply parentheses

8m-(2(+m-22/4))-8+3=0

We multiply all the terms by the denominator


8m*4))-(2(+m-22-8*4))+3*4))=0

We add all the numbers together, and all the variables

8m*4))-(2(m-54))+3*4))=0

We add all the numbers together, and all the variables

8m*4))-(2(m=0

Wy multiply elements

32m^2=0

a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{64}=0$