8(-1+m)+3=2(m-5/12)

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Solution for 8(-1+m)+3=2(m-5/12) equation:



8(-1+m)+3=2(m-5/12)
We move all terms to the left:
8(-1+m)+3-(2(m-5/12))=0
We add all the numbers together, and all the variables
8(m-1)-(2(+m-5/12))+3=0
We multiply parentheses
8m-(2(+m-5/12))-8+3=0
We multiply all the terms by the denominator
8m*12))-(2(+m-5-8*12))+3*12))=0
We add all the numbers together, and all the variables
8m*12))-(2(m-101))+3*12))=0
We add all the numbers together, and all the variables
8m*12))-(2(m=0
Wy multiply elements
96m^2=0
a = 96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·96·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{192}=0$

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