8(-1+m)+3=2(m-51/5

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Solution for 8(-1+m)+3=2(m-51/5 equation: 



8(-1+m)+3=2(m-51/5

We move all terms to the left:

8(-1+m)+3-(2(m-51/5)=0

We add all the numbers together, and all the variables

8(m-1)-(2(+m-51/5)+3=0

We multiply parentheses

8m-(2(+m-51/5)+3-8=0

We multiply all the terms by the denominator


8m*5)+3-8-(2(+m-51=0

Wy multiply elements

40m^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{80}=0$

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