8(-11a+1)=-7(1+12a)+11a

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Solution for 8(-11a+1)=-7(1+12a)+11a equation: 



8(-11a+1)=-7(1+12a)+11a

We move all terms to the left:

8(-11a+1)-(-7(1+12a)+11a)=0

We add all the numbers together, and all the variables

8(-11a+1)-(-7(12a+1)+11a)=0

We multiply parentheses

-88a-(-7(12a+1)+11a)+8=0



We calculate terms in parentheses: -(-7(12a+1)+11a), so:

-7(12a+1)+11a

We add all the numbers together, and all the variables

11a-7(12a+1)

We multiply parentheses

11a-84a-7

We add all the numbers together, and all the variables

-73a-7

Back to the equation:

-(-73a-7)



We get rid of parentheses

-88a+73a+7+8=0

We add all the numbers together, and all the variables

-15a+15=0

We move all terms containing a to the left, all other terms to the right

-15a=-15

a=-15/-15

a=1

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