8(-2b-11)=10(4-8b)

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Solution for 8(-2b-11)=10(4-8b) equation: 



8(-2b-11)=10(4-8b)

We move all terms to the left:

8(-2b-11)-(10(4-8b))=0

We add all the numbers together, and all the variables

8(-2b-11)-(10(-8b+4))=0

We multiply parentheses

-16b-(10(-8b+4))-88=0



We calculate terms in parentheses: -(10(-8b+4)), so:

10(-8b+4)

We multiply parentheses

-80b+40

Back to the equation:

-(-80b+40)



We get rid of parentheses

-16b+80b-40-88=0

We add all the numbers together, and all the variables

64b-128=0

We move all terms containing b to the left, all other terms to the right

64b=128

b=128/64

b=2

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