8(-2x+1)=-10(x+2)+28-6x

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Solution for 8(-2x+1)=-10(x+2)+28-6x equation: 


Simplifying
8(-2x + 1) = -10(x + 2) + 28 + -6x

Reorder the terms:
8(1 + -2x) = -10(x + 2) + 28 + -6x
(1 * 8 + -2x * 8) = -10(x + 2) + 28 + -6x
(8 + -16x) = -10(x + 2) + 28 + -6x

Reorder the terms:
8 + -16x = -10(2 + x) + 28 + -6x
8 + -16x = (2 * -10 + x * -10) + 28 + -6x
8 + -16x = (-20 + -10x) + 28 + -6x

Reorder the terms:
8 + -16x = -20 + 28 + -10x + -6x

Combine like terms: -20 + 28 = 8
8 + -16x = 8 + -10x + -6x

Combine like terms: -10x + -6x = -16x
8 + -16x = 8 + -16x

Add '-8' to each side of the equation.
8 + -8 + -16x = 8 + -8 + -16x

Combine like terms: 8 + -8 = 0
0 + -16x = 8 + -8 + -16x
-16x = 8 + -8 + -16x

Combine like terms: 8 + -8 = 0
-16x = 0 + -16x
-16x = -16x

Add '16x' to each side of the equation.
-16x + 16x = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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