8(-3+2x)=6(2x-4)+8

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Solution for 8(-3+2x)=6(2x-4)+8 equation:



8(-3+2x)=6(2x-4)+8
We move all terms to the left:
8(-3+2x)-(6(2x-4)+8)=0
We add all the numbers together, and all the variables
8(2x-3)-(6(2x-4)+8)=0
We multiply parentheses
16x-(6(2x-4)+8)-24=0
We calculate terms in parentheses: -(6(2x-4)+8), so:
6(2x-4)+8
We multiply parentheses
12x-24+8
We add all the numbers together, and all the variables
12x-16
Back to the equation:
-(12x-16)
We get rid of parentheses
16x-12x+16-24=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2

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