8(-3+2x)=6(2x-4)+8

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Solution for 8(-3+2x)=6(2x-4)+8 equation: 



8(-3+2x)=6(2x-4)+8

We move all terms to the left:

8(-3+2x)-(6(2x-4)+8)=0

We add all the numbers together, and all the variables

8(2x-3)-(6(2x-4)+8)=0

We multiply parentheses

16x-(6(2x-4)+8)-24=0



We calculate terms in parentheses: -(6(2x-4)+8), so:

6(2x-4)+8

We multiply parentheses

12x-24+8

We add all the numbers together, and all the variables

12x-16

Back to the equation:

-(12x-16)



We get rid of parentheses

16x-12x+16-24=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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