8(-3y-8)=-6(5y+5)+20

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Solution for 8(-3y-8)=-6(5y+5)+20 equation: 



8(-3y-8)=-6(5y+5)+20

We move all terms to the left:

8(-3y-8)-(-6(5y+5)+20)=0

We multiply parentheses

-24y-(-6(5y+5)+20)-64=0



We calculate terms in parentheses: -(-6(5y+5)+20), so:

-6(5y+5)+20

We multiply parentheses

-30y-30+20

We add all the numbers together, and all the variables

-30y-10

Back to the equation:

-(-30y-10)



We get rid of parentheses

-24y+30y+10-64=0

We add all the numbers together, and all the variables

6y-54=0

We move all terms containing y to the left, all other terms to the right

6y=54

y=54/6

y=9

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