8(-7y-5)=-8y-40

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Solution for 8(-7y-5)=-8y-40 equation: 



8(-7y-5)=-8y-40

We move all terms to the left:

8(-7y-5)-(-8y-40)=0

We multiply parentheses

-56y-(-8y-40)-40=0

We get rid of parentheses

-56y+8y+40-40=0

We add all the numbers together, and all the variables

-48y=0

y=0/-48

y=0

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