8(-b-4)=-40

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Solution for 8(-b-4)=-40 equation: 



8(-b-4)=-40

We move all terms to the left:

8(-b-4)-(-40)=0

We add all the numbers together, and all the variables

8(-1b-4)-(-40)=0

We add all the numbers together, and all the variables

8(-1b-4)+40=0

We multiply parentheses

-8b-32+40=0

We add all the numbers together, and all the variables

-8b+8=0

We move all terms containing b to the left, all other terms to the right

-8b=-8

b=-8/-8

b=1

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