8(-b-4)=48

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Solution for 8(-b-4)=48 equation: 



8(-b-4)=48

We move all terms to the left:

8(-b-4)-(48)=0

We add all the numbers together, and all the variables

8(-1b-4)-48=0

We multiply parentheses

-8b-32-48=0

We add all the numbers together, and all the variables

-8b-80=0

We move all terms containing b to the left, all other terms to the right

-8b=80

b=80/-8

b=-10

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