8(-x-5)+2x=-40+2x

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Solution for 8(-x-5)+2x=-40+2x equation: 



8(-x-5)+2x=-40+2x

We move all terms to the left:

8(-x-5)+2x-(-40+2x)=0

We add all the numbers together, and all the variables

8(-1x-5)+2x-(2x-40)=0

We add all the numbers together, and all the variables

2x+8(-1x-5)-(2x-40)=0

We multiply parentheses

2x-8x-(2x-40)-40=0

We get rid of parentheses

2x-8x-2x+40-40=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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