8(1+2b)-4(b-8)=4+6b+6

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Solution for 8(1+2b)-4(b-8)=4+6b+6 equation: 



8(1+2b)-4(b-8)=4+6b+6

We move all terms to the left:

8(1+2b)-4(b-8)-(4+6b+6)=0

We add all the numbers together, and all the variables

8(2b+1)-4(b-8)-(6b+10)=0

We multiply parentheses

16b-4b-(6b+10)+8+32=0

We get rid of parentheses

16b-4b-6b-10+8+32=0

We add all the numbers together, and all the variables

6b+30=0

We move all terms containing b to the left, all other terms to the right

6b=-30

b=-30/6

b=-5

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