8(1+2k)=-2(k-4)

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Solution for 8(1+2k)=-2(k-4) equation: 



8(1+2k)=-2(k-4)

We move all terms to the left:

8(1+2k)-(-2(k-4))=0

We add all the numbers together, and all the variables

8(2k+1)-(-2(k-4))=0

We multiply parentheses

16k-(-2(k-4))+8=0



We calculate terms in parentheses: -(-2(k-4)), so:

-2(k-4)

We multiply parentheses

-2k+8

Back to the equation:

-(-2k+8)



We get rid of parentheses

16k+2k-8+8=0

We add all the numbers together, and all the variables

18k=0

k=0/18

k=0

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