8(1+3b)=40=8b

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Solution for 8(1+3b)=40=8b equation: 



8(1+3b)=40=8b

We move all terms to the left:

8(1+3b)-(40)=0

We add all the numbers together, and all the variables

8(3b+1)-40=0

We multiply parentheses

24b+8-40=0

We add all the numbers together, and all the variables

24b-32=0

We move all terms containing b to the left, all other terms to the right

24b=32

b=32/24

b=1+1/3

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