8(1+4b)+8b=128

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Solution for 8(1+4b)+8b=128 equation:


Simplifying
8(1 + 4b) + 8b = 128
(1 * 8 + 4b * 8) + 8b = 128
(8 + 32b) + 8b = 128

Combine like terms: 32b + 8b = 40b
8 + 40b = 128

Solving
8 + 40b = 128

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 40b = 128 + -8

Combine like terms: 8 + -8 = 0
0 + 40b = 128 + -8
40b = 128 + -8

Combine like terms: 128 + -8 = 120
40b = 120

Divide each side by '40'.
b = 3

Simplifying
b = 3

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