8(1+a)=-3a-(a+4)

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Solution for 8(1+a)=-3a-(a+4) equation: 



8(1+a)=-3a-(a+4)

We move all terms to the left:

8(1+a)-(-3a-(a+4))=0

We add all the numbers together, and all the variables

8(a+1)-(-3a-(a+4))=0

We multiply parentheses

8a-(-3a-(a+4))+8=0



We calculate terms in parentheses: -(-3a-(a+4)), so:

-3a-(a+4)

We get rid of parentheses

-3a-a-4

We add all the numbers together, and all the variables

-4a-4

Back to the equation:

-(-4a-4)



We get rid of parentheses

8a+4a+4+8=0

We add all the numbers together, and all the variables

12a+12=0

We move all terms containing a to the left, all other terms to the right

12a=-12

a=-12/12

a=-1

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