8(1+b)=4(b-12)

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Solution for 8(1+b)=4(b-12) equation: 



8(1+b)=4(b-12)

We move all terms to the left:

8(1+b)-(4(b-12))=0

We add all the numbers together, and all the variables

8(b+1)-(4(b-12))=0

We multiply parentheses

8b-(4(b-12))+8=0



We calculate terms in parentheses: -(4(b-12)), so:

4(b-12)

We multiply parentheses

4b-48

Back to the equation:

-(4b-48)



We get rid of parentheses

8b-4b+48+8=0

We add all the numbers together, and all the variables

4b+56=0

We move all terms containing b to the left, all other terms to the right

4b=-56

b=-56/4

b=-14

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