8(1+m)+3=(m-51/2

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Solution for 8(1+m)+3=(m-51/2 equation: 



8(1+m)+3=(m-51/2

We move all terms to the left:

8(1+m)+3-((m-51/2)=0

We add all the numbers together, and all the variables

8(m+1)-((+m-51/2)+3=0

We multiply parentheses

8m-((+m-51/2)+3+8=0

We multiply all the terms by the denominator


8m*2)+3+8-((+m-51=0

Wy multiply elements

16m^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{32}=0$

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