8(1+y)=7(8+y0=

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Solution for 8(1+y)=7(8+y0= equation: 



8(1+y)=7(8+y0=

We move all terms to the left:

8(1+y)-(7(8+y0)=0

We add all the numbers together, and all the variables

8(y+1)-(7(y+8)=0

We multiply parentheses

8y-(7(y+8)+8=0

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