8(1-2b)=-8(1+b)

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Solution for 8(1-2b)=-8(1+b) equation: 



8(1-2b)=-8(1+b)

We move all terms to the left:

8(1-2b)-(-8(1+b))=0

We add all the numbers together, and all the variables

8(-2b+1)-(-8(b+1))=0

We multiply parentheses

-16b-(-8(b+1))+8=0



We calculate terms in parentheses: -(-8(b+1)), so:

-8(b+1)

We multiply parentheses

-8b-8

Back to the equation:

-(-8b-8)



We get rid of parentheses

-16b+8b+8+8=0

We add all the numbers together, and all the variables

-8b+16=0

We move all terms containing b to the left, all other terms to the right

-8b=-16

b=-16/-8

b=+2

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