8(1-2x)=-6(2x-1)-(4x-2)

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Solution for 8(1-2x)=-6(2x-1)-(4x-2) equation:


Simplifying
8(1 + -2x) = -6(2x + -1) + -1(4x + -2)
(1 * 8 + -2x * 8) = -6(2x + -1) + -1(4x + -2)
(8 + -16x) = -6(2x + -1) + -1(4x + -2)

Reorder the terms:
8 + -16x = -6(-1 + 2x) + -1(4x + -2)
8 + -16x = (-1 * -6 + 2x * -6) + -1(4x + -2)
8 + -16x = (6 + -12x) + -1(4x + -2)

Reorder the terms:
8 + -16x = 6 + -12x + -1(-2 + 4x)
8 + -16x = 6 + -12x + (-2 * -1 + 4x * -1)
8 + -16x = 6 + -12x + (2 + -4x)

Reorder the terms:
8 + -16x = 6 + 2 + -12x + -4x

Combine like terms: 6 + 2 = 8
8 + -16x = 8 + -12x + -4x

Combine like terms: -12x + -4x = -16x
8 + -16x = 8 + -16x

Add '-8' to each side of the equation.
8 + -8 + -16x = 8 + -8 + -16x

Combine like terms: 8 + -8 = 0
0 + -16x = 8 + -8 + -16x
-16x = 8 + -8 + -16x

Combine like terms: 8 + -8 = 0
-16x = 0 + -16x
-16x = -16x

Add '16x' to each side of the equation.
-16x + 16x = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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