8(1-2y)+5=3(1-2y)-10y+10

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Solution for 8(1-2y)+5=3(1-2y)-10y+10 equation: 


Simplifying
8(1 + -2y) + 5 = 3(1 + -2y) + -10y + 10
(1 * 8 + -2y * 8) + 5 = 3(1 + -2y) + -10y + 10
(8 + -16y) + 5 = 3(1 + -2y) + -10y + 10

Reorder the terms:
8 + 5 + -16y = 3(1 + -2y) + -10y + 10

Combine like terms: 8 + 5 = 13
13 + -16y = 3(1 + -2y) + -10y + 10
13 + -16y = (1 * 3 + -2y * 3) + -10y + 10
13 + -16y = (3 + -6y) + -10y + 10

Reorder the terms:
13 + -16y = 3 + 10 + -6y + -10y

Combine like terms: 3 + 10 = 13
13 + -16y = 13 + -6y + -10y

Combine like terms: -6y + -10y = -16y
13 + -16y = 13 + -16y

Add '-13' to each side of the equation.
13 + -13 + -16y = 13 + -13 + -16y

Combine like terms: 13 + -13 = 0
0 + -16y = 13 + -13 + -16y
-16y = 13 + -13 + -16y

Combine like terms: 13 + -13 = 0
-16y = 0 + -16y
-16y = -16y

Add '16y' to each side of the equation.
-16y + 16y = -16y + 16y

Combine like terms: -16y + 16y = 0
0 = -16y + 16y

Combine like terms: -16y + 16y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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