8(1-3b)+1=-3-4(2b-3)

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Solution for 8(1-3b)+1=-3-4(2b-3) equation: 



8(1-3b)+1=-3-4(2b-3)

We move all terms to the left:

8(1-3b)+1-(-3-4(2b-3))=0

We add all the numbers together, and all the variables

8(-3b+1)-(-3-4(2b-3))+1=0

We multiply parentheses

-24b-(-3-4(2b-3))+8+1=0



We calculate terms in parentheses: -(-3-4(2b-3)), so:

-3-4(2b-3)

determiningTheFunctionDomain
-4(2b-3)-3

We multiply parentheses

-8b+12-3

We add all the numbers together, and all the variables

-8b+9

Back to the equation:

-(-8b+9)



We add all the numbers together, and all the variables

-24b-(-8b+9)+9=0

We get rid of parentheses

-24b+8b-9+9=0

We add all the numbers together, and all the variables

-16b=0

b=0/-16

b=0

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