8(1-4v)+2=-6(1+6v)+2v

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Solution for 8(1-4v)+2=-6(1+6v)+2v equation: 



8(1-4v)+2=-6(1+6v)+2v

We move all terms to the left:

8(1-4v)+2-(-6(1+6v)+2v)=0

We add all the numbers together, and all the variables

8(-4v+1)-(-6(6v+1)+2v)+2=0

We multiply parentheses

-32v-(-6(6v+1)+2v)+8+2=0



We calculate terms in parentheses: -(-6(6v+1)+2v), so:

-6(6v+1)+2v

We add all the numbers together, and all the variables

2v-6(6v+1)

We multiply parentheses

2v-36v-6

We add all the numbers together, and all the variables

-34v-6

Back to the equation:

-(-34v-6)



We add all the numbers together, and all the variables

-32v-(-34v-6)+10=0

We get rid of parentheses

-32v+34v+6+10=0

We add all the numbers together, and all the variables

2v+16=0

We move all terms containing v to the left, all other terms to the right

2v=-16

v=-16/2

v=-8

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