8(1-K)=3(k+12)

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Solution for 8(1-K)=3(k+12) equation: 



8(1-)=3(K+12)

We move all terms to the left:

8(1-)-(3(K+12))=0

We add all the numbers together, and all the variables

-(3(K+12))+80=0



We calculate terms in parentheses: -(3(K+12)), so:

3(K+12)

We multiply parentheses

3K+36

Back to the equation:

-(3K+36)



We get rid of parentheses

-3K-36+80=0

We add all the numbers together, and all the variables

-3K+44=0

We move all terms containing K to the left, all other terms to the right

-3K=-44

K=-44/-3

K=14+2/3

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