8(1-b)=-10-(-b+9)

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Solution for 8(1-b)=-10-(-b+9) equation: 



8(1-b)=-10-(-b+9)

We move all terms to the left:

8(1-b)-(-10-(-b+9))=0

We add all the numbers together, and all the variables

8(-1b+1)-(-10-(-1b+9))=0

We multiply parentheses

-8b-(-10-(-1b+9))+8=0



We calculate terms in parentheses: -(-10-(-1b+9)), so:

-10-(-1b+9)

determiningTheFunctionDomain
-(-1b+9)-10

We get rid of parentheses

1b-9-10

We add all the numbers together, and all the variables

b-19

Back to the equation:

-(b-19)



We get rid of parentheses

-8b-b+19+8=0

We add all the numbers together, and all the variables

-9b+27=0

We move all terms containing b to the left, all other terms to the right

-9b=-27

b=-27/-9

b=+3

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