8(1-k)+20(k-2)=1

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Solution for 8(1-k)+20(k-2)=1 equation: 



8(1-k)+20(k-2)=1

We move all terms to the left:

8(1-k)+20(k-2)-(1)=0

We add all the numbers together, and all the variables

8(-1k+1)+20(k-2)-1=0

We multiply parentheses

-8k+20k+8-40-1=0

We add all the numbers together, and all the variables

12k-33=0

We move all terms containing k to the left, all other terms to the right

12k=33

k=33/12

k=2+3/4

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