8(1-r)-8(-2+7r)=-40

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Solution for 8(1-r)-8(-2+7r)=-40 equation: 



8(1-r)-8(-2+7r)=-40

We move all terms to the left:

8(1-r)-8(-2+7r)-(-40)=0

We add all the numbers together, and all the variables

8(-1r+1)-8(7r-2)-(-40)=0

We add all the numbers together, and all the variables

8(-1r+1)-8(7r-2)+40=0

We multiply parentheses

-8r-56r+8+16+40=0

We add all the numbers together, and all the variables

-64r+64=0

We move all terms containing r to the left, all other terms to the right

-64r=-64

r=-64/-64

r=1

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