8(1-x)+2(4+x)=3(6+3x)-9(x-2)

Solution for 8(1-x)+2(4+x)=3(6+3x)-9(x-2) equation:

8(1-x)+2(4+x)=3(6+3x)-9(x-2)

We move all terms to the left:

8(1-x)+2(4+x)-(3(6+3x)-9(x-2))=0

We add all the numbers together, and all the variables

8(-1x+1)+2(x+4)-(3(3x+6)-9(x-2))=0

We multiply parentheses

-8x+2x-(3(3x+6)-9(x-2))+8+8=0


We calculate terms in parentheses: -(3(3x+6)-9(x-2)), so:

3(3x+6)-9(x-2)

We multiply parentheses

9x-9x+18+18

We add all the numbers together, and all the variables

36

Back to the equation:

-(36)


We add all the numbers together, and all the variables

-6x-20=0

We move all terms containing x to the left, all other terms to the right

-6x=20

x=20/-6

x=-3+1/3