8(1-x)-10=2(4-3x)

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Solution for 8(1-x)-10=2(4-3x) equation:



8(1-x)-10=2(4-3x)
We move all terms to the left:
8(1-x)-10-(2(4-3x))=0
We add all the numbers together, and all the variables
8(-1x+1)-(2(-3x+4))-10=0
We multiply parentheses
-8x-(2(-3x+4))+8-10=0
We calculate terms in parentheses: -(2(-3x+4)), so:
2(-3x+4)
We multiply parentheses
-6x+8
Back to the equation:
-(-6x+8)
We add all the numbers together, and all the variables
-8x-(-6x+8)-2=0
We get rid of parentheses
-8x+6x-8-2=0
We add all the numbers together, and all the variables
-2x-10=0
We move all terms containing x to the left, all other terms to the right
-2x=10
x=10/-2
x=-5

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