8(1-y)-3(y+2)=2(y+1)

Solution for 8(1-y)-3(y+2)=2(y+1) equation:

Simplifying
8(1 + -1y) + -3(y + 2) = 2(y + 1)
(1 * 8 + -1y * 8) + -3(y + 2) = 2(y + 1)
(8 + -8y) + -3(y + 2) = 2(y + 1)

Reorder the terms:
8 + -8y + -3(2 + y) = 2(y + 1)
8 + -8y + (2 * -3 + y * -3) = 2(y + 1)
8 + -8y + (-6 + -3y) = 2(y + 1)

Reorder the terms:
8 + -6 + -8y + -3y = 2(y + 1)

Combine like terms: 8 + -6 = 2
2 + -8y + -3y = 2(y + 1)

Combine like terms: -8y + -3y = -11y
2 + -11y = 2(y + 1)

Reorder the terms:
2 + -11y = 2(1 + y)
2 + -11y = (1 * 2 + y * 2)
2 + -11y = (2 + 2y)

Add '-2' to each side of the equation.
2 + -2 + -11y = 2 + -2 + 2y

Combine like terms: 2 + -2 = 0
0 + -11y = 2 + -2 + 2y
-11y = 2 + -2 + 2y

Combine like terms: 2 + -2 = 0
-11y = 0 + 2y
-11y = 2y

Solving
-11y = 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-11y + -2y = 2y + -2y

Combine like terms: -11y + -2y = -13y
-13y = 2y + -2y

Combine like terms: 2y + -2y = 0
-13y = 0

Divide each side by '-13'.
y = 0

Simplifying
y = 0