8(1-y)-3y=6(2-y)

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Solution for 8(1-y)-3y=6(2-y) equation: 



8(1-y)-3y=6(2-y)

We move all terms to the left:

8(1-y)-3y-(6(2-y))=0

We add all the numbers together, and all the variables

8(-1y+1)-3y-(6(-1y+2))=0

We add all the numbers together, and all the variables

-3y+8(-1y+1)-(6(-1y+2))=0

We multiply parentheses

-3y-8y-(6(-1y+2))+8=0



We calculate terms in parentheses: -(6(-1y+2)), so:

6(-1y+2)

We multiply parentheses

-6y+12

Back to the equation:

-(-6y+12)



We add all the numbers together, and all the variables

-11y-(-6y+12)+8=0

We get rid of parentheses

-11y+6y-12+8=0

We add all the numbers together, and all the variables

-5y-4=0

We move all terms containing y to the left, all other terms to the right

-5y=4

y=4/-5

y=-4/5

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