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8(1/4x-3)+24=4(x+5)+4
We move all terms to the left:
8(1/4x-3)+24-(4(x+5)+4)=0
Domain of the equation: 4x-3)!=0We multiply parentheses
x∈R
8x-(4(x+5)+4)-24+24=0
We calculate terms in parentheses: -(4(x+5)+4), so:We add all the numbers together, and all the variables
4(x+5)+4
We multiply parentheses
4x+20+4
We add all the numbers together, and all the variables
4x+24
Back to the equation:
-(4x+24)
8x-(4x+24)=0
We get rid of parentheses
8x-4x-24=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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