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8(1/8x+3)-12=x+12
We move all terms to the left:
8(1/8x+3)-12-(x+12)=0
Domain of the equation: 8x+3)!=0We multiply parentheses
x∈R
8x-(x+12)+24-12=0
We get rid of parentheses
8x-x-12+24-12=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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