8(13-k)=4(2k-2)

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Solution for 8(13-k)=4(2k-2) equation: 



8(13-k)=4(2k-2)

We move all terms to the left:

8(13-k)-(4(2k-2))=0

We add all the numbers together, and all the variables

8(-1k+13)-(4(2k-2))=0

We multiply parentheses

-8k-(4(2k-2))+104=0



We calculate terms in parentheses: -(4(2k-2)), so:

4(2k-2)

We multiply parentheses

8k-8

Back to the equation:

-(8k-8)



We get rid of parentheses

-8k-8k+8+104=0

We add all the numbers together, and all the variables

-16k+112=0

We move all terms containing k to the left, all other terms to the right

-16k=-112

k=-112/-16

k=+7

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