8(1c+2)-2(2c-1)=2(6c+5)

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Solution for 8(1c+2)-2(2c-1)=2(6c+5) equation: 



8(1c+2)-2(2c-1)=2(6c+5)

We move all terms to the left:

8(1c+2)-2(2c-1)-(2(6c+5))=0

We add all the numbers together, and all the variables

8(c+2)-2(2c-1)-(2(6c+5))=0

We multiply parentheses

8c-4c-(2(6c+5))+16+2=0



We calculate terms in parentheses: -(2(6c+5)), so:

2(6c+5)

We multiply parentheses

12c+10

Back to the equation:

-(12c+10)



We add all the numbers together, and all the variables

4c-(12c+10)+18=0

We get rid of parentheses

4c-12c-10+18=0

We add all the numbers together, and all the variables

-8c+8=0

We move all terms containing c to the left, all other terms to the right

-8c=-8

c=-8/-8

c=1

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