8(1x*1x)=36

Solution for 8(1x*1x)=36 equation:

8(1x*1x)=36

We move all terms to the left:

8(1x*1x)-(36)=0

We add all the numbers together, and all the variables

8(+1x*1x)-36=0

We multiply parentheses

8x^2-36=0

a = 8; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·8·(-36)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*8}=\frac{0-24\sqrt{2}}{16}
=-\frac{24\sqrt{2}}{16}
=-\frac{3\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*8}=\frac{0+24\sqrt{2}}{16}
=\frac{24\sqrt{2}}{16}
=\frac{3\sqrt{2}}{2}
$